Section 1.4, problem 3
Find the general solution to:
xy' = (y - x)³ + y
Expanding the bracket and dividing everything by x³ we get:Using a change of variable where u = y/x and y' = u + u'x we get:
Simplifying we get:
Separating the variables by cross multiplication and then integrating both sides we have:
Some re-arrangement is necessary before we can convert back to y from u.
Converting back to y from u we have:
Section 1.4, Problem 4
Find the general solution of:
xy' = y² + y
Dividing by x² we get:
Change of variable using u = y/x and y' = u + u'x gives:
This simplifies to:
u' = u²
Integrating, we get:
Re-arranging:Changing back to y from u gives
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